document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=428152>Question 428152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a proof says:\r<BR>\n" );
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document.write( "\"Given: Triangle CDF is an isosceles triangle whose shortest side is line segment FD.\" \r<BR>\n" );
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document.write( "Is that the same as perpendicular? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297665 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297665\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "No.\r<BR>\n" );
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document.write( "An isosceles triangle has two sides of equal measure.  Hence, the third side is either longer than each of the two equal sides or shorter than each of the two equal sides.\r<BR>\n" );
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document.write( "In order for FD to be the shortest side, the triangle must represent the latter condition and FD is the one unequal side.  You can also deduce that segments CD and CF are congruent.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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