document.write( "Question 428131: 3x+4y=15
\n" ); document.write( "-4x-3y=-20\r
\n" ); document.write( "\n" ); document.write( "I need to solve this through the addition method. Is there an easy way to do this?
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Algebra.Com's Answer #297645 by htmentor(1343)\"\" \"About 
You can put this solution on YOUR website!
If, by addition method you mean adding one equation to the other, then proceed as follows:
\n" ); document.write( " 3x + 4y = 15 (1)
\n" ); document.write( "-4x - 3y = -20 (2)
\n" ); document.write( "First multiply equation (1) by 4 and equation (2) by 3:
\n" ); document.write( "12x + 16y = 60
\n" ); document.write( "-12x - 9y = -60
\n" ); document.write( "Add the two equations:
\n" ); document.write( "7y = 0 -> y = 0
\n" ); document.write( "Substituting into equation (1) above, we get:
\n" ); document.write( "3x = 15 -> x = 5
\n" ); document.write( "So the solution is x = 5, y = 0
\n" ); document.write( "Below are the graphs of the two functions:
\n" ); document.write( "\"graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C15%2F4-3%2F4%2Ax%2C20%2F3-4%2F3%2Ax%29\"
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