document.write( "Question 428131: 3x+4y=15
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document.write( "-4x-3y=-20\r
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document.write( "I need to solve this through the addition method. Is there an easy way to do this? \n" );
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Algebra.Com's Answer #297645 by htmentor(1343)![]() ![]() You can put this solution on YOUR website! If, by addition method you mean adding one equation to the other, then proceed as follows: \n" ); document.write( " 3x + 4y = 15 (1) \n" ); document.write( "-4x - 3y = -20 (2) \n" ); document.write( "First multiply equation (1) by 4 and equation (2) by 3: \n" ); document.write( "12x + 16y = 60 \n" ); document.write( "-12x - 9y = -60 \n" ); document.write( "Add the two equations: \n" ); document.write( "7y = 0 -> y = 0 \n" ); document.write( "Substituting into equation (1) above, we get: \n" ); document.write( "3x = 15 -> x = 5 \n" ); document.write( "So the solution is x = 5, y = 0 \n" ); document.write( "Below are the graphs of the two functions: \n" ); document.write( " |