document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=427991>Question 427991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two numbers are in the ratio 1:3. If i add 2 to each of the numbers, the ratio becomes 1:2. Find the number. PLease write it in the form of algebraic equation.<BR>\n" );
document.write( "Thank You! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297581 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297581\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let one number be x 	<BR>\n" );
document.write( "let other number be y<BR>\n" );
document.write( "x/y	=	 1/3				<BR>\n" );
document.write( "cross multiply	3	x   	=	1	y		<BR>\n" );
document.write( "3x -y =0	...........1		<BR>\n" );
document.write( "( X +2)/(y+2)=	½<BR>\n" );
document.write( "2(x+2)=	1(y+2)2x+4=y+2	<BR>\n" );
document.write( "2x-y=-2	............2		<BR>\n" );
document.write( "Multiply (1) by 	-1	we get						<BR>\n" );
document.write( "-3x-y=0	............3		<BR>\n" );
document.write( "Add (3)&(2)						<BR>\n" );
document.write( "-x=-2			<BR>\n" );
document.write( "x=2				<BR>\n" );
document.write( "2 & 6 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );