document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=428026>Question 428026</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A scientist has one alloy containing 39% copper and another containing 61% copper. How many pounds of each alloy must he use to make 41 pounds of a third alloy containing 48% copper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297577 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .........percent	----------------	quantity							<BR>\n" );
document.write( "Alloy 1	39	----------------	x	pounds						<BR>\n" );
document.write( "Alloy 2	61	----------------	41-x	pounds						<BR>\n" );
document.write( "Total	48%	----------------	41									<BR>\n" );
document.write( "												<BR>\n" );
document.write( "39x+61(41-x)=48*	41<BR>\n" );
document.write( "												<BR>\n" );
document.write( "39x+2501	-61x=1968		<BR>\n" );
document.write( "39x-61x=	1968-2501		<BR>\n" );
document.write( "-22x=-533							<BR>\n" );
document.write( "/-22											<BR>\n" );
document.write( "x=24.23	pounds	39.00%		<BR>\n" );
document.write( "16.77 pounds 61.00%		<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );