document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=427704>Question 427704</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The exercise asks to solve algebraically this equation: 36(1.35)^x=4.35 My work comes up as: 36(1.35)^x-4.35=0 However, I have a key: approx. 8.024 Obviously, my work is wrong, and I wonder if I have to solve it using log but I am not sure about the steps. Can you help me to do it, please? Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297572 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297572\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The exercise asks to solve algebraically this equation: 36(1.35)^x=4.35 My work comes up as: 36(1.35)^x-4.35=0 However, I have a key: approx. 8.024 Obviously, my work is wrong, and I wonder if I have to solve it using log but I am not sure about the steps. <BR>\n" );
document.write( "..<BR>\n" );
document.write( "Usually, when you need to solve a variable that is an exponent, logarithms are required.<BR>\n" );
document.write( "36(1.35)^x=4.35<BR>\n" );
document.write( "(1.35)^x=4.35/36<BR>\n" );
document.write( "taking logs of both sides using the exponent  and division rules of logarithms.<BR>\n" );
document.write( "xlog(1.35)=log(4.35)-log(36)<BR>\n" );
document.write( "x=[log(4.35)-log(36)]/log(1.35)<BR>\n" );
document.write( "using calculator<BR>\n" );
document.write( "x=-7.0420..<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "36*1.35^-7.042=4.35 </SPAN>\n" );
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