document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=428018>Question 428018</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A grocer wants to mix two kinds of coffee.One kind sells for $1.35 per pound, the other sells for 2.65 per pound. He wants to mix a total of 16 pounds and sell them for $2.05 per pound. How many pounds of each kind should he use in the new mix? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297569 by </B><A HREF=/tutors/aboutme.mpl?userid=John10><B>John10(297)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=John10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=John10><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297569\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A grocer wants to mix two kinds of coffee.One kind sells for $1.35 per pound, the other sells for 2.65 per pound. He wants to mix a total of 16 pounds and sell them for $2.05 per pound. How many pounds of each kind should he use in the new mix?\r<BR>\n" );
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document.write( "Let x be $1.35 per pound coffee and y is $ 2.65 per pound coffee\r<BR>\n" );
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document.write( "x + y = 16 (Total)\r<BR>\n" );
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document.write( "1.35x + 2.65y = (16)*(2.05) (Price)\r<BR>\n" );
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document.write( "Solve the above system to find x and y\r<BR>\n" );
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document.write( "Hint: x = 7.4 lbs and y = 8.6 lbs (These values are rounded)\r<BR>\n" );
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document.write( "Hope it will help you! Thanks </SPAN>\n" );
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