document.write( "Question 427984: 0.1x+0.7y=-2.3
\n" ); document.write( "0.3x-0.2y=2.3\r
\n" ); document.write( "\n" ); document.write( "solve the system using substitution method \n" ); document.write( "
Algebra.Com's Answer #297547 by mananth(16949)\"\" \"About 
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0.1x+0.7y=-2.3
\n" ); document.write( "0.3x-0.2y=2.3
\n" ); document.write( "multiply both equations by 10\r
\n" ); document.write( "\n" ); document.write( "x+7y=-23
\n" ); document.write( "3x-2y=23\r
\n" ); document.write( "\n" ); document.write( "x+7y=-23 .............1
\n" ); document.write( "-2y=23-3 x---------2
\n" ); document.write( "/-2
\n" ); document.write( "y=-11.5- 1.5x
\n" ); document.write( "Plug the value of y in (1)
\n" ); document.write( "x+7(-11.5+1.5x)= -23
\n" ); document.write( "x-80.5+10.5x)=-23
\n" ); document.write( "x+10.5x= -23
\n" ); document.write( "11.5x=57.5
\n" ); document.write( "/11.5
\n" ); document.write( "x=5
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "x+7y=-23
\n" ); document.write( "5+7y=-23
\n" ); document.write( "5+7y=-23
\n" ); document.write( "7y=-28
\n" ); document.write( "/7
\n" ); document.write( "y=-4
\n" ); document.write( " \n" ); document.write( "
\n" );