document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=427900>Question 427900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a certain sum of money is invested in a business. each year this investment earns 1.5 times as much as in the preceding year. if the investment earned a total of $19,500 in 4 years, how much did it earn in the fourth year? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297545 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297545\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If X number of dollars are invested with a return of 150% (1.5 times the principal), then our equation for the four years is:\r<BR>\n" );
document.write( "\n" );
document.write( "X+1.5X+2.25X+3.375X+5.0625X=X+19,500<BR>\n" );
document.write( "12.1875X=19500<BR>\n" );
document.write( "X=1600\r<BR>\n" );
document.write( "\n" );
document.write( "So our principal was $1600.  Our interest for the fourth year was 5.0625 times $1600 or $8100.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );