document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=427939>Question 427939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pure acid is to be added to a 5% acid solution to obtain 95L of 89% solution. What amounts of each should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297536 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297536\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.05x + 1.00(95 - x) = 0.89*95<BR>\n" );
document.write( "==> 0.05x + 95 - x = 84.55<BR>\n" );
document.write( "==> -0.95x = -10.45<BR>\n" );
document.write( "==> x = 11 liters, the amount of 5% acid solution, and <BR>\n" );
document.write( "95 - x = 84 liters, the amount of 89% acid solution. </SPAN>\n" );
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