document.write( "Question 427905: find the three consecutive odd integers
\n" );
document.write( "such that three times the smallest
\n" );
document.write( "plus four times the largest will result
\n" );
document.write( "in the middle integer plus 104. \n" );
document.write( "
Algebra.Com's Answer #297511 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! \"find the three consecutive odd integers \n" ); document.write( "such that three times the smallest \n" ); document.write( "plus four times the largest will result \n" ); document.write( "in the middle integer plus 104.\"\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 1st consecutive odd integer \n" ); document.write( "x + 2 = 2nd consecutive odd integer \n" ); document.write( "x + 4 = 3rd consecutive odd integer\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x + 4(x + 4) = x + 2 + 104 {three times smallest plus four times largest equals middle plus 104} \n" ); document.write( "3x + 4x + 16 = x + 2 + 104 {used distributive property} \n" ); document.write( "7x + 16 = x + 106 {combined like terms} \n" ); document.write( "7x = x + 90 {subtracted 16 from both sides{ \n" ); document.write( "6x = 90 {subtracted x from both sides} \n" ); document.write( "x = 15 {divided both sides by 6} \n" ); document.write( "x + 2 = 17 {substituted 15, in for x, into x + 2} \n" ); document.write( "x + 4 = 19 {substituted 15, in for x, into x + 4}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "15, 17, and 19 are the three consecutive odd integers \n" ); document.write( "www.algebrahouse.com \n" ); document.write( " |