document.write( "Question 427683: A boy is twice as old as his brother - 4 years ago he was 3 times as old as his brother. What are their present ages? \n" ); document.write( "
Algebra.Com's Answer #297443 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! If boy X is twice as old as his brother Y right now, then X = 2Y. Four years ago he was three times as old as his brother, so X - 4=3(Y - 4).\r \n" ); document.write( "\n" ); document.write( "X-4 = 3(Y-4) \n" ); document.write( "X-4 = 3Y-12\r \n" ); document.write( "\n" ); document.write( "If X=2Y, then \n" ); document.write( "2Y-4=3Y-12 \n" ); document.write( "2Y+8=3Y \n" ); document.write( "8=Y\r \n" ); document.write( "\n" ); document.write( "The brother is now 8 years old, and the boy is 2(8) or 16 years old. \n" ); document.write( " |