document.write( "Question 44886: How many liters (L) of a 10% silver iodide solution must be mixed with 7 L of a 4% silver iodide solution to get a 6% solution? \n" ); document.write( "
Algebra.Com's Answer #29740 by stanbon(75887)\"\" \"About 
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How many liters (L) of a 10% silver iodide solution must be mixed with 7 L of a 4% silver iodide solution to get a 6% solution? \r
\n" ); document.write( "\n" ); document.write( "Start: 7L of 4% solution has 0.04(7)=0.28 liters of active ingredient\r
\n" ); document.write( "\n" ); document.write( "Add: x liters of 10% solution which has 0.10x liters of active ingredient\r
\n" ); document.write( "\n" ); document.write( "End up with: x+7 liters of 6% solution which has 0.06(x+7) liters of active
\n" ); document.write( "ingredient.\r
\n" ); document.write( "\n" ); document.write( "EQUATION:
\n" ); document.write( "active + active = active
\n" ); document.write( "0.28 + 0.10x=0.06x+0.42\r
\n" ); document.write( "\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "28 +10x = 6x + 42
\n" ); document.write( "4x = 14
\n" ); document.write( "x=7/2= 3.5 liters (amount of 10% solution you need to add)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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