document.write( "Question 427601: pls. help me solve this problem... thank you\r
\n" ); document.write( "\n" ); document.write( "a normal distribution has the mean of 160.5. if 75% of the area under the curve lies to the left of 185.2 find:
\n" ); document.write( " a. the area to the left of 160.5
\n" ); document.write( " b. the area to the right of 185.2
\n" ); document.write( " c. the area between 160.5 and 185.2
\n" ); document.write( " d. the standard deviation
\n" ); document.write( " e. the area betweem 160.5 and 180.5
\n" ); document.write( " f. the area to the right of 180.5 \n" ); document.write( "

Algebra.Com's Answer #297386 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "a normal distribution has the mean of 160.5. 
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document.write( "if 75% of the area under the curve lies to the left of 185.2
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document.write( "a. the area to the left of 160.5(μ) is 50%
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document.write( "b. the area to the right of 185.2  is 25%
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document.write( "c. the area between 160.5 and 185.2 is 25%
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document.write( "d. the standard deviation:  z(P =.75) = .67449 = (185.2-160.5)/σ   σ = 36.62
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document.write( "e. the area betweem 160.5 and 180.5:  z = 20/36.62 = .5461 and P =.7075
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document.write( "  A = 70.75% - 50% = 20.75%
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document.write( "f. the area to the right of 180.5 is 29.25%\r
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document.write( "Below... left of the blue line, is 75% of the area under the curve
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