document.write( "Question 427624: The average diameter of certain Euro coins 3.00 millimeters with a standard deviation of
\n" ); document.write( "0.70 millimeters. If 9 coins are chosen at random, find the probability that the average
\n" ); document.write( "diameter of those coins is more than 2.790 millimeters. Assume that the variable is
\n" ); document.write( "normally distributed.
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Algebra.Com's Answer #297384 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
\n" ); document.write( "Note: \"z+=blue+%28x+-+mu%29%2Fblue%28sigma%2Fsqrt%28n%29%29\"
\n" ); document.write( " z = (2.79-3.00) / .7/3 = -.21 *3/.7 = -.9
\n" ); document.write( "P(z > -.9) = probability that the average diameter is more than 2.790mm \n" ); document.write( "
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