document.write( "Question 427517: Bill invested a total of $8000 in two accounts, one paying 10% interest and the other paying 15% interest. If the total interest earned was $1000, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #297317 by mananth(16946)\"\" \"About 
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Part I 10.00% per annum
\n" ); document.write( "Part II 15.00% per annum
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\n" ); document.write( "x+y=8000 ------------------------1
\n" ); document.write( "10.00%x +15.00% y=$1,000.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "10x+15y =$100,000.00--------2
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\n" ); document.write( "Multiply (1) by -10
\n" ); document.write( "we get
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\n" ); document.write( "-10x-10y =-80000
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\n" ); document.write( "Add this to (2)
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\n" ); document.write( "5y= $20,000.00
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\n" ); document.write( "divide by 5
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\n" ); document.write( "y=$4,000.00 investment at 15%
\n" ); document.write( "Balance $4,000.00 investment at 10%
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