document.write( "Question 427517: Bill invested a total of $8000 in two accounts, one paying 10% interest and the other paying 15% interest. If the total interest earned was $1000, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #297317 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Part I 10.00% per annum \n" ); document.write( "Part II 15.00% per annum \n" ); document.write( " \n" ); document.write( "x+y=8000 ------------------------1 \n" ); document.write( "10.00%x +15.00% y=$1,000.00 \n" ); document.write( "Multiply by 100 \n" ); document.write( "10x+15y =$100,000.00--------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -10 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-10x-10y =-80000 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "5y= $20,000.00 \n" ); document.write( " \n" ); document.write( "divide by 5 \n" ); document.write( " \n" ); document.write( "y=$4,000.00 investment at 15% \n" ); document.write( "Balance $4,000.00 investment at 10% \n" ); document.write( " \n" ); document.write( " |