document.write( "Question 427553: Please help me set up this problem:\r
\n" ); document.write( "\n" ); document.write( "\"A canoe can travel 15 mph in still water. Going with the current it can travel 20 miles in the same time that it takes to travel 10 miles against the current. Find the rate of the current.\"
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Algebra.Com's Answer #297307 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
boat speed =15 mph
\n" ); document.write( "current speed =x mph
\n" ); document.write( "Speed upstream= 15-x
\n" ); document.write( "Speed downstream=15+x
\n" ); document.write( "Distance upstream= 10 miles
\n" ); document.write( "Distance downstream= 20 miles
\n" ); document.write( "t=d/r time upstream = time downstream
\n" ); document.write( "10/(15-x )=20/(15 +x)
\n" ); document.write( "10(15+x)=20(15-x)
\n" ); document.write( "150+10x=300-20x
\n" ); document.write( "20x-10x=150
\n" ); document.write( "10 x = 150
\n" ); document.write( "/ 10
\n" ); document.write( "x =15mph current speed
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