document.write( "Question 427553: Please help me set up this problem:\r
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document.write( "\"A canoe can travel 15 mph in still water. Going with the current it can travel 20 miles in the same time that it takes to travel 10 miles against the current. Find the rate of the current.\" \n" );
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Algebra.Com's Answer #297305 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A canoe can travel 15 mph in still water. \n" ); document.write( "Going with the current it can travel 20 miles in the same time that it takes to travel 10 miles against the current. \n" ); document.write( "Find the rate of the current \n" ); document.write( "----- \n" ); document.write( "With-current DATA: \n" ); document.write( "distance = 20 miles ; rate = 15+c mph; time = d/r = 20/(15+c) hrs \n" ); document.write( "---- \n" ); document.write( "Against-current DATA: \n" ); document.write( "distance = 10 miles ; rate = 15-c mph; time = d/r = 10/(15-c) hrs \n" ); document.write( "-------------- \n" ); document.write( "Equation: \n" ); document.write( "time = time \n" ); document.write( "20/(15+c) = 10/(15-c) \n" ); document.write( "Cross-multiply to get: \n" ); document.write( "20(15-c) = 10(15+c) \n" ); document.write( "300-20c = 150+10c \n" ); document.write( "30c = 150 \n" ); document.write( "c = 5 mph (speed of the current) \n" ); document.write( "==================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |