document.write( "Question 427491: write the equation of a circle whose diameter has endpoints (2,-7) and (2,1). \n" ); document.write( "
Algebra.Com's Answer #297279 by Gogonati(855)\"\" \"About 
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Solution: The center of circle is: X0=2+2/2=2 and Y0=-7+1/2=-3, center is (2,-3)
\n" ); document.write( "and
\n" ); document.write( "\"+d=+sqrt+%28%282-2%29%5E2%2B%281%2B7%29%5E2%29\", d=8 and r=4 As we know the equation of circle\r
\n" ); document.write( "\n" ); document.write( "Centered at (X0,Y0) and radius r is: \"%28X-X0%29%5E2%2B%28Y-Y0%29%5E2=R%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Substituting our given results: \"%28x-2%29%5E2%2B%28y%2B3%29%5E2=16\" is the equation of circle. \r
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