document.write( "Question 427425: Write the slope-intercept equation for the line that passes through (-12, 10) and is perpendicular to 4x + 6y = 3 \n" ); document.write( "

Algebra.Com's Answer #297269 by John10(297) $\"\"$ $\"About$

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Write the slope-intercept equation for the line that passes through (-12, 10) and is perpendicular to 4x + 6y = 3 \r
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\n" ); document.write( "First find the slope of the given line:\r
\n" ); document.write( "\n" ); document.write( "Write the equation i slope-intercept form: y = mx + b\r
\n" ); document.write( "\n" ); document.write( "4x + 6y = 3
\n" ); document.write( "6y = -4x + 3
\n" ); document.write( "y = (-2/3)x + 1/2\r
\n" ); document.write( "\n" ); document.write( "Since the given line is perpendicular with the new line, their slopes product is -1.\r
\n" ); document.write( "\n" ); document.write( "Let m be the slope of the new line: (-2/3)m = -1\r
\n" ); document.write( "\n" ); document.write( "m = -1 * (-3/2) = 3/2\r
\n" ); document.write( "\n" ); document.write( "Now we use the slope m = 3/2 and (-12, 10) to find the equation\r
\n" ); document.write( "\n" ); document.write( "y -10 = 3/2 (x +12)\r
\n" ); document.write( "\n" ); document.write( "y -10 = (3/2)x + 18\r
\n" ); document.write( "\n" ); document.write( "y = (3/2)x + 28\r
\n" ); document.write( "\n" ); document.write( "This is the line that we need to find!Hope it will help you!\r
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