document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=427404>Question 427404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jessie and Philip are on opposite side of a road that is 5 miles long. Jessie is walking toward Philip at 4mph and Philip is riding his bike at 6mph toward Jessie. In how many minutes will they meet each other? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297254 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297254\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since both Jessie and Philip are approaching each other, we can take their respective speeds and add them together to get an answer.\r<BR>\n" );
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document.write( "4mph + 6mph = 10mph\r<BR>\n" );
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document.write( "Since the distance between them is 5 miles, we get:<BR>\n" );
document.write( "5 miles/10 miles/hour, or 1/2 hour before they meet. </SPAN>\n" );
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