document.write( "Question 427284: A hiker begins a 25 km(point B) hike from point A at 7am travelling at a rate of 4km per hour. At 9:30, a bike rider leaves point B travelling at a rate of 16 km per hour. What time will the hiker and biker cross paths (meet)? At what kilometer will they meet? \n" ); document.write( "
Algebra.Com's Answer #297155 by mananth(16946)\"\" \"About 
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Hiker 4 km/h
\n" ); document.write( "Biker 16 km/h 2.5 hours late
\n" ); document.write( "Distance 25 miles
\n" ); document.write( "In 2.5 hours Hiker has traveled 10 miles before Biker starts
\n" ); document.write( "So distance = 15 when Biker starts
\n" ); document.write( "Let time they meet be x hours
\n" ); document.write( "Hiker distance traveled 4x miles
\n" ); document.write( "Biker distance traveled 16(15 -x)
\n" ); document.write( "
\n" ); document.write( "Time taken to meet is same
\n" ); document.write( "t=d/r
\n" ); document.write( "combined speed= 20 mph
\n" ); document.write( "
\n" ); document.write( "20x=15
\n" ); document.write( "x= 0.75 hours
\n" ); document.write( "Hiker 4x=3 miles
\n" ); document.write( "Hiker would have traveled 3+10=13 miles
\n" ); document.write( "Biker (25-13)=12 miles
\n" ); document.write( "They will cross at 10:15 AM \n" ); document.write( "
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