document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=427258>Question 427258</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6 ducks and 5 pigs cost 213 dollars, while 2 ducks and 9 pigs cost 269 dollars.  find the cost of a duck and a pig </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #297123 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=297123\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 6 ducks and 5 pigs cost $213, then we have: 6D + 5P=213<BR>\n" );
document.write( "2 ducks and 9 pigs cost $269, so:  2D + 9P=269.  We multiply the second equation through by 3 and we get:  6D + 27P=807.  <BR>\n" );
document.write( "  6D + 27P=807<BR>\n" );
document.write( "- 6D +  5P=213<BR>\n" );
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document.write( "       22P=594\r<BR>\n" );
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document.write( "         P=27<BR>\n" );
document.write( "807 - 27(27)= 78 = 6D<BR>\n" );
document.write( "              13 = D\r<BR>\n" );
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document.write( "Pigs cost $27 apiece, and ducks cost $13 apiece. </SPAN>\n" );
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