Algebra.Com's Answer #297052 by nerdybill(7384)  You can put this solution on YOUR website! Applying log rules: \n" );
document.write( "ln x + ln (x-2) = 1 \n" );
document.write( "ln x(x-2) = 1 \n" );
document.write( "x(x-2) = e^1 \n" );
document.write( "x^2-2x = e^1 \n" );
document.write( "x^2-2x - e^1 = 0 \n" );
document.write( "x^2-2x - 2.718 = 0 \n" );
document.write( "applying the quadratic formula we get: \n" );
document.write( "x = {2.928, -0.928} \n" );
document.write( "you can throw out the negative solution leaving: \n" );
document.write( "x = 2.928 \n" );
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document.write( "details of quadratic follows: \n" );
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document.write( " Solved by pluggable solver: SOLVE quadratic equation with variable | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " Discriminant d=14.872 is greater than zero. That means that there are two solutions: . \n" );
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document.write( " Quadratic expression can be factored: \n" );
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document.write( " Again, the answer is: 2.92821160664487, -0.928211606644872.\n" );
document.write( "Here's your graph: \n" );
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