document.write( "Question 427073: Please help. Thank you\r
\n" ); document.write( "\n" ); document.write( "Write the slope-intercept equation for the line that passes through (14, -2) and is perpendicular to 7x – 10y = 18 Please show all of your work \n" ); document.write( "

Algebra.Com's Answer #297013 by Gogonati(855) $\"\"$ $\"About$

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Solution:First we find the slope of 7x-10y=18 => -10y=18-7x => $\"y=%287%2F10%29%2Ax-%2818%2F10%29\"$ \r
\n" ); document.write( "\n" ); document.write( "From the last equation we see the slope is $\"m%5B1%5D=7%2F10\"$ . As we know the perpendicular lines have negative reciprocal slopes, thus the slope of our line is $\"m%5B2%5D=-10%2F7\"$ , and the equation of our line that passes at (14,-2) is given:\r
\n" ); document.write( "\n" ); document.write( " $\"y%2B2=%28-10%2F7%29%2A%28x-14%29\"$ , simplify this equation:\r
\n" ); document.write( "\n" ); document.write( " 7y+14=-10x+140 => 7y=-10x+126 => $\"y=%28-10%2F7%29x%2B126\"$ \r
\n" ); document.write( "\n" ); document.write( " Answer: The slope-intercept equation is: $\"y=%28-10%2F7%29%2Ax%2B126\"$ \r
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