document.write( "Question 427061: Solve the following system of equations using substitution.\r
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document.write( "2x+4y=12
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document.write( "4x+16y=8\r
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document.write( "I substituted 2x+4y for x in the second equation and I ended up with 8x+32y=8. I've tried so many of these problems and I just can't understand them. \n" );
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Algebra.Com's Answer #297009 by Gogonati(855)![]() ![]() You can put this solution on YOUR website! Solution:First we simplify the system dividing the first equation by 2 and the second by 4,and the system can be written:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The second equation is a linear equation of one variable. We solve this equation with respect to y:\r \n" ); document.write( "\n" ); document.write( "6+2y=2 => 2y=-4 => y=-2. Substitute this value of y in the first equation and find x: x=6-2(-2) => x=10. The ordered pair (10, -2) is the solution of our system.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |