document.write( "Question 427061: Solve the following system of equations using substitution.\r
\n" ); document.write( "\n" ); document.write( "2x+4y=12
\n" ); document.write( "4x+16y=8\r
\n" ); document.write( "\n" ); document.write( "I substituted 2x+4y for x in the second equation and I ended up with 8x+32y=8. I've tried so many of these problems and I just can't understand them.
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Algebra.Com's Answer #297007 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Hi
\n" ); document.write( "Note: the idea solving using substitution is for that to result
\n" ); document.write( "in an equation with ONE unknown.\r
\n" ); document.write( "\n" ); document.write( "2x+4y=12 OR x = 6-2y |solving for x
\n" ); document.write( "4x+16y=8 |Substituting that into the 2nd EQ
\n" ); document.write( "4(6-2y)+16y = 8 |now we have an EQ with ONE unknown
\n" ); document.write( "solving for y
\n" ); document.write( " 24 - 8y + 16y = 8
\n" ); document.write( " 8y = -16
\n" ); document.write( " y = -2 and x = 10 (6- 2*-2)\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " 4x+16y=8
\n" ); document.write( " 40 -32=8 \n" ); document.write( "
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