document.write( "Question 427063: solve the system of equations using the addition method.\r
\n" ); document.write( "\n" ); document.write( "equ 1: 2x-1/5y=-5
\n" ); document.write( "equ 2: 3x-5/2y=-37/2\r
\n" ); document.write( "\n" ); document.write( "I have tried tried multiplying -5 to (equ 1) to take out the fraction and
\n" ); document.write( "and -2 to (equ 2) and I'm not sure if that's correct so far.\r
\n" ); document.write( "\n" ); document.write( "Answer: equ 1: 10x+y=25
\n" ); document.write( " equ 2: 6xt10y=74 \n" ); document.write( "

Algebra.Com's Answer #297006 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi, 
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document.write( "would like to accomplish eliminating the y-terms in one step:
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document.write( "solve the system of equations using the addition method.
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document.write( " 2x-(1/5)y=-5
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document.write( " 3x-(5/2)y=-37/2\r
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document.write( " -25x +(5/2)y = 125/2  |Mulitplying 1st EQ by -25/2 Note: = -25x
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document.write( "  3x  -(5/2)y = -37/2
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document.write( "       -22x = 88/2 = 44
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document.write( "         x = -2  and y = (2x+5)5 = 5
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document.write( "Ordered pair (-2,5) the solution for this system\r
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document.write( "CHECKING our Answer***
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document.write( " 3x -(5/2)y= -37/2
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document.write( " -6 - 25/2 =  -12/2 - 25/2 = -37/2 \n" );
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