document.write( "Question 427006: Given the polynomial P(x)=2x^3-x^2-13x-6 and one of its factors:x+2.
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Algebra.Com's Answer #296984 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
There are three zeros, since it's a third degree polynomial (fundamental theorem of algebra).\r
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\n" ); document.write( "\n" ); document.write( "Divide \"P%28x%29+=+%282x%5E3+-+x%5E2+-+13x+-+6%29%2F%28x%2B2%29\" using either long or synthetic division. You should obtain \"2x%5E2+-+5x+-+3\". We find the other zeros of the function using the quadratic equation:\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%285+%2B-+sqrt%2825+%2B+24%29%29%2F4+=+%285+%2B-+7%29%2F4\" = 3 or -1/2. Hence, this polynomial factors to \"%28x-3%29%28x%2B1%2F2%29\" and P(x) is equal to \"%28x-3%29%28x%2B1%2F2%29%28x%2B2%29\".
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