document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426967>Question 426967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find 4 consecutive numbers whose sum is 15 less than 5 times the first.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296976 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296976\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the (first) lowest number<BR>\n" );
document.write( "Then the other numbers are x+1, x+2 and x+3<BR>\n" );
document.write( "Given: sum is less than 5 times the first.<BR>\n" );
document.write( "In equation form this is:<BR>\n" );
document.write( "x + x+1 + x+2 + x+3 = 5x - 15<BR>\n" );
document.write( "Now collect terms and solve for x:<BR>\n" );
document.write( "4x + 6 = 5x - 15 -> x = 21<BR>\n" );
document.write( "So the 4 numbers are:<BR>\n" );
document.write( "21, 22, 23, 24<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "21 + 22 + 23 + 24 = 90<BR>\n" );
document.write( "5(21) = 105<BR>\n" );
document.write( "105 - 90 = 15, so sum is 15 less than 5 times the first<BR>\n" );
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