document.write( "Question 426965: (Compound value solving for n)How many years will the following take?\r
\n" ); document.write( "\n" ); document.write( "a) $500 to grow to $1,039.50 invested at 5 percent compounded annually
\n" ); document.write( "b) $35 to grow to $53.87 invested at 9 percent compounded annually
\n" ); document.write( "c) $100 to grow to $298.60 invested at 20 percent compounded annually
\n" ); document.write( "d) $53 to grow to $78.76 invested at 2 percent compounded annually\r
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Algebra.Com's Answer #296954 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Note: In genernal, A= p(1+r/n) ^nt 
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document.write( "Compounded annually; A = p(1+r)^t  OR   log(A/p) /log(1+r) = t\r
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document.write( "a) $500 to grow to $1,039.50 invested at 5 percent compounded annually
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document.write( "   log(1039.50/500)/log(1.05) = 15yr\r
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document.write( "b) $35 to grow to $53.87 invested at 9 percent compounded annually
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document.write( "   log(53.87/35)/log(1.09) = t\r
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document.write( "c) $100 to grow to $298.60 invested at 20 percent compounded annually
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document.write( "   log(298.60/100)/log(1.20) = t\r
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document.write( "d) $53 to grow to $78.76 invested at 2 percent compounded annually 
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document.write( "   log(78.76/53)/log(1.02) = t\r
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