document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426924>Question 426924</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, can anyone help me with these two questions on series and sequences?:\r<BR>\n" );
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document.write( "1) For the sequence 15,12,9,... find the common difference and the nth term.\r<BR>\n" );
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document.write( "2) If 3x-1, 2x+2 and 2x-1 are in Arithmetic Progression, find value of x.\r<BR>\n" );
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document.write( "Thank you for your time and consideration! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296951 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution: 1)The common difference is d=12-15=9-12=-3 and the nth term is:\r<BR>\n" );
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document.write( "         <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5Bn%5D=a%5B1%5D-%28n-1%29d ALIGN=MIDDLE  ALT=\"a%5Bn%5D=a%5B1%5D-%28n-1%29d\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "         <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5Bn%5D=15-%28n-1%293 ALIGN=MIDDLE  ALT=\"a%5Bn%5D=15-%28n-1%293\"   DISABLED_style= \"max-width:90%; height:auto;\" >, simplify the formula\r<BR>\n" );
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document.write( "          <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5Bn%5D=18-3n ALIGN=MIDDLE  ALT=\"a%5Bn%5D=18-3n\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( " 2)Since the sequence: 3x-1, 2x+2, 2x-1 is an arithmetic progression we have:\r<BR>\n" );
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document.write( "     (2x+2)-(3x-1)=(2x-1)-(2x+2) => -x+1=-3 => x=4. </SPAN>\n" );
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