document.write( "Question 44817: I'm stuck on this one. Do I plug something into something? Not sure what book this is from.\r
\n" ); document.write( "\n" ); document.write( "Let f(x)= 2/x + 1/x-1. Find all a for which f(a)= f(a+1).\r
\n" ); document.write( "\n" ); document.write( "Thanks!
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Algebra.Com's Answer #29695 by adamchapman(301)\"\" \"About 
You can put this solution on YOUR website!
f(a)=f(a+1) means that the function has the same value x=1 and when x=(a+1)
\n" ); document.write( "\"f%28x%29=2%2Fx%2B1%2F%28x-1%29\"
\n" ); document.write( "so:
\n" ); document.write( "\"2%2Fa%2B1%2F%28a-1%29=2%2F%28a%2B1%29%2B1%2Fa\"
\n" ); document.write( "Now rearrange to find a:
\n" ); document.write( "\"2%2B%28a%2B1%29%2F%28a-1%29=2%28a%2B1%29%2B%28a%2B1%29%2Fa\"
\n" ); document.write( "\"2%28a-1%29%2B%28a%2B1%29=2%28a%2B1%29%28a-1%29%2B%28a%2B1%29%28a-1%29%2Fa\"
\n" ); document.write( "\"2a%28a-1%29%2B%28a%2B1%29a=2a%28a%2B1%29%28a-1%29%2B%28a%2B1%29%28a-1%29\"
\n" ); document.write( "\"2a%5E2-a%2Ba%5E2%2Ba=2a%28a%5E2-1%29%2B%28a%5E2-1%29\"
\n" ); document.write( "\"3a%5E2=2a%5E3-2a%5E2%2B%28a%5E2-1%29\"
\n" ); document.write( "\"3a%5E2=2a%5E3-a%5E2-1\"
\n" ); document.write( "\"2a%5E3-4a%5E2-1=0\"
\n" ); document.write( "Use this link:
\n" ); document.write( "http://www.1728.com/cubic2.htm
\n" ); document.write( "to find the root(s) of this equation.
\n" ); document.write( "I hope this helps.
\n" ); document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk
\n" ); document.write( "Adam\r
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