document.write( "Question 426979: Find standard. Form or parabola when directix is y=4 and focus is (6,-6) \n" ); document.write( "

Algebra.Com's Answer #296949 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( " Using The standard form is , where the focus is (h,k + p) 
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document.write( "Find standard form of parabola when directix is y=4 and focus is (6,-6)
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document.write( "Note the vertex is 'halfway' (along the line of symmetry, x = 6) 
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document.write( "between the directrix: y = 4 and the focus (6,-6).(this parabola opens downward)
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document.write( "distance between directrix and focus: 4-(-6) = 10 , 10/2 = 5...  
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document.write( "p = -5... therefore, the Vertex Pt is (6,-1)
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document.write( " (x-6)^2 = -20(y+1)  OR y = (-1/20)(x-6)^2 - 1
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