document.write( "Question 426853: A person invested $10,000. The greater part is invested at 6% and the remainder at 5%. The annual income from the greater part is $160 more than the annual income from the smaller part. What is the smaller part of the investement? \n" ); document.write( "

Algebra.Com's Answer #296934 by mananth(16946) $\"\"$ $\"About$

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Part I 6.00% per annum------------- x
\n" ); document.write( "Part II 5.00% per annum------------ y
\n" ); document.write( "total investment 10000
\n" ); document.write( "Interest----- from greater part = 6.00%of x
\n" ); document.write( "Interest from smaller part= 5.00% of y
\n" ); document.write( "greater by $160
\n" ); document.write( "6.00%x= 5.00%y+160
\n" ); document.write( "multiply by 100
\n" ); document.write( "6x-5y= 16000 --------1
\n" ); document.write( "x+y=10000 -------- 2
\n" ); document.write( "eliminate y
\n" ); document.write( "Multiply 1 by 1
\n" ); document.write( "Multiply 2 by 5
\n" ); document.write( "we get
\n" ); document.write( "6x-5y=16000
\n" ); document.write( "5x-5y=50000
\n" ); document.write( "11x=66000
\n" ); document.write( "/11
\n" ); document.write( "x=6000
\n" ); document.write( "Plug the value of x in in 1
\n" ); document.write( "36000-5y=16000
\n" ); document.write( "-5y=16000-36000
\n" ); document.write( "-5y=-20000
\n" ); document.write( "/-5
\n" ); document.write( "y=4000
\n" ); document.write( "$6000 at 6.00%
\n" ); document.write( "$4000 at 5.00%
\n" ); document.write( " \n" ); document.write( "

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