document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426952>Question 426952</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How would I set this problem up? A Cupronickel alloy that is 60% copper and 40% nickel is needed to manufacturea marine propeller. Only two cupronickel alloys are available, one is 75% copper and 25% nickel and the other is 55% copper and 45% nickel. How many pounds of each of these alloys need to be melted and combined to obtain 300 pounds of the 60% copper/ 40% nickel alloy?  I am havin trouble because there are two metals that need to be melted together and I'm not sure of what I am supposed to do. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296925 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296925\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem is set to just see your analatical ability. ( OR confuse you)\r<BR>\n" );
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document.write( "If you have 60% copper then naturally you will have 40% Nickel in the final alloy.\r<BR>\n" );
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document.write( "So lets say we need 60% copper in the alloy.\r<BR>\n" );
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document.write( "--------percent	----------------quantity							<BR>\n" );
document.write( "Alloy 1	75	----------------x	pounds						<BR>\n" );
document.write( "Alloy 2	55	----------------300-x	pounds			<BR>\n" );
document.write( "Total	60.00%	----------------300					<BR>\n" );
document.write( "75x+55(300-x)=	60*300<BR>\n" );
document.write( "75x+16500-55x=18000		<BR>\n" );
document.write( "75x-55x	=18000	-16500		<BR>\n" );
document.write( "20x=1500							<BR>\n" );
document.write( "/20											<BR>\n" );
document.write( "x=75 pounds	75.00%	Alloy	<BR>\n" );
document.write( "225 pounds of 55.00%	Alloy\r<BR>\n" );
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document.write( "---------------------<BR>\n" );
document.write( "Work the other way using Nickel as the required %. you get the same quantities.\r<BR>\n" );
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document.write( "---------percent----------------quantity							<BR>\n" );
document.write( "Alloy 1	25	----------------x	pounds						<BR>\n" );
document.write( "Alloy 2	45	----------------300-x	pounds						<BR>\n" );
document.write( "Total	5.00%	----------------300					<BR>\n" );
document.write( "25x+45(300-x)=40*300<BR>\n" );
document.write( "25x+13500-45x=12000		<BR>\n" );
document.write( "25x-45x	=12000-13500		<BR>\n" );
document.write( "-20x=	-1500							<BR>\n" );
document.write( "/-20											<BR>\n" );
document.write( "x=75 pounds	25.00% 		<BR>\n" );
document.write( "												<BR>\n" );
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document.write( "					225			pounds		45.00%		\r<BR>\n" );
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document.write( " </SPAN>\n" );
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