document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426888>Question 426888</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor f(x) into linear factors given that k is a zero of f(x)<BR>\n" );
document.write( "f(x)=x^3-3x^2-36x+108; k=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296913 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296913\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x)=x^3-3x^2-36x+108<BR>\n" );
document.write( "If k is a zero of f(x) then 6 is a zero of f(x)<BR>\n" );
document.write( "therefore x=6 and x-6 is a factor.<BR>\n" );
document.write( "(x^3-3x^2-36x+108)/(x-6)=x^2+3x-18<BR>\n" );
document.write( "x^2+3x-18=(x+6)(x-3) the other two factors.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );