document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426907>Question 426907</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the area if a rectangle is 143 sq feet and the perimeter is 48 feet, what are the dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296900 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lw=A, 2(L+w)=P<BR>\n" );
document.write( "Lw=143<BR>\n" );
document.write( "2(L+w)=48<BR>\n" );
document.write( "L+w=24<BR>\n" );
document.write( "L=24-w<BR>\n" );
document.write( "w(24-w)=143<BR>\n" );
document.write( "-w^2+24w=143<BR>\n" );
document.write( "w^2-24w=-143<BR>\n" );
document.write( "w^2-24w+143=0<BR>\n" );
document.write( "(w-13)(w-11)=0<BR>\n" );
document.write( "w=11, L=13 or vice versa.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );