document.write( "Question 426919: a rectangular painting has the dimensions x and x+10. the painting is in a frame 2 inches wide. the total area of the picture and the frame is 936 in. what are the total dimensions of the painting
\n" ); document.write( "this is my problme solving question and my formula for solving ( factoring ) was ( x+2) (x+12)=936 i multiplied out and got x²+14x+24=936. i just don't understand where to go after i use completing the square and getting x=-38 and x=29 how do i find the dimensions from two x values \n" ); document.write( "
Algebra.Com's Answer #296899 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
Your approach is right. But the area of the rectangle is actually (X+4)(X+14)=936 because you have to add 2 inches to each side to form a 2-inch border. Thus we have:
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\n" ); document.write( "(X+4)(X+10+4)=936
\n" ); document.write( "(X+4)(X+14)=936
\n" ); document.write( "X^2 + 18X + 56 = 936
\n" ); document.write( "X^2 + 18X - 880 = 0
\n" ); document.write( "(X+40)(X-22) = 0
\n" ); document.write( "X = -40 or 22\r
\n" ); document.write( "\n" ); document.write( "We reject the negative answer, and we're left with X = 22. If we check this we get (22+4)(22+14)= 936, 26*36 = 936, 936 = 936.\r
\n" ); document.write( "\n" ); document.write( "Edited 3-13-2017
\n" ); document.write( "x * x+10=936
\n" ); document.write( "x²+10x-936=0
\n" ); document.write( "(x+36)(x-26)=0
\n" ); document.write( "x=-36 or 26
\n" ); document.write( "x+10=36
\n" ); document.write( "The dimensions of the entire picture and frame is 36\" x 26\". The dimensions of the picture itself is (36-4)x(26-4), or 32\" by 22\". ☺☺☺☺ \n" ); document.write( "
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