document.write( "Question 426890: A boat took 1 hour and 50 minutes to go 55 miles downstream and 3 hours and 40 minutes to return. What is the rate of the current? \n" ); document.write( "

Algebra.Com's Answer #296880 by mananth(16946) $\"\"$ $\"About$

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against current 3.67 hours
\n" ); document.write( "with current 1.83 hours
\n" ); document.write( "
\n" ); document.write( "Distance = same=55
\n" ); document.write( "boat speed =x
\n" ); document.write( "current speed =y
\n" ); document.write( "t=d/r
\n" ); document.write( "55/(x-y)=3.67
\n" ); document.write( "3.67(x-y)=55.00
\n" ); document.write( "3.67x-3.67y= 55 ....................1
\n" ); document.write( "55/(x+y)=1.83
\n" ); document.write( "1.83(x+y)=55
\n" ); document.write( "1.83x+1.83y= 55 ...............2
\n" ); document.write( "Multiply (1) by 1.83
\n" ); document.write( "Multiply (2) by 3.67
\n" ); document.write( "we get
\n" ); document.write( "6.72x-6.72y= 100.83
\n" ); document.write( "6.73x+6.73y= 201.85
\n" ); document.write( "13.45 x=302.68
\n" ); document.write( "/13.45
\n" ); document.write( "x=22.5mph boat speed
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\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "3.67x-3.67y= 55
\n" ); document.write( "82.51-3.67y= 55
\n" ); document.write( "-3.67 y= 55 -82.51
\n" ); document.write( "-3.67 y= -27.51
\n" ); document.write( " y= 7.5 mph current speed
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