document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426609>Question 426609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am 60 and was born on July 29, 1950.\r<BR>\n" );
document.write( "\n" );
document.write( "My son just turned 30 and was born on March 18, 1981.\r<BR>\n" );
document.write( "\n" );
document.write( "On what date will my son be or was my son exactly half my age?\r<BR>\n" );
document.write( "\n" );
document.write( "I am a teacher myself (language) and it has been a really long time since I have done math! I swear, things like finding out the percentage I can do but this one has stumped me.\r<BR>\n" );
document.write( "\n" );
document.write( "Thank you for your kind response! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296867 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296867\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am 60 and was born on July 29, 1950.<BR>\n" );
document.write( "My son just turned 30 and was born on March 18, 1981.<BR>\n" );
document.write( "On what date will my son be or was my son exactly half my age?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "On the son's 30th birthday, man will be 60 + 232 days old (Jul29 to Mar18)<BR>\n" );
document.write( ": <BR>\n" );
document.write( "Let x = no. of days for man to be twice as old as son, (after Mar 18)<BR>\n" );
document.write( "60 + (x+232) = 2(30 + x)<BR>\n" );
document.write( "60 + (x+232) = 60 + 2x<BR>\n" );
document.write( "Subtract 60 from both sides<BR>\n" );
document.write( "x + 232 = 2x<BR>\n" );
document.write( "232 = 2x - x<BR>\n" );
document.write( "x = 232 days after son's birthday, he will half as old as Dad<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Find the date 232 days after son's birthday,  that's Nov 8th , man will be twice as old as son.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "That will be 232 + 232 days = 464 days from Man's 60th birthday<BR>\n" );
document.write( "In 464 days he will be 1 yr + 99 days older<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check using the their ages as decimals<BR>\n" );
document.write( "Man's age on Nov 8: 61<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=99%2F365 ALIGN=MIDDLE  ALT=\"99%2F365\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 61.27133<BR>\n" );
document.write( "Son's age on Nov 8: 30<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=232%2F365 ALIGN=MIDDLE  ALT=\"232%2F365\"   DISABLED_style= \"max-width:90%; height:auto;\" >= 30.63562<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Check the fraction: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30.63562%2F61.27133 ALIGN=MIDDLE  ALT=\"30.63562%2F61.27133\"   DISABLED_style= \"max-width:90%; height:auto;\" > ~ .5 \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );