document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426825>Question 426825</A>: <I><SPAN STYLE=\"word-break: break-all;\"> for the function f(x)=-ln(x+2) if x = -1.9,-1,1,5? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296840 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296840\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for the function f(x)=-ln(x+2) if x = -1.9,-1,1,5?<BR>\n" );
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document.write( "Sub the values for x.<BR>\n" );
document.write( "f(-1.9 - -ln(-1.9 + 2) = ln(0.1)<BR>\n" );
document.write( "Use a calculator<BR>\n" );
document.write( "ln(0.1) =~ -2.302585<BR>\n" );
document.write( "-ln = +2.302585<BR>\n" );
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document.write( "Do the same for the other 2 values\r<BR>\n" );
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