document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426731>Question 426731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the length of the diagonal of a rectangle that has a width of 3 inches and a perimeter of 14 inches? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296818 by </B><A HREF=/tutors/aboutme.mpl?userid=Adrish><B>Adrish(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Adrish><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solutions: Given: width=3inches<BR>\n" );
document.write( "Perimeter=14 inches\r<BR>\n" );
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document.write( "Diagonal= Sqrt(length^2 + Width^2)\r<BR>\n" );
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document.write( "First we will find the length\r<BR>\n" );
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document.write( "P=2L + 2W<BR>\n" );
document.write( "14=2L +2x3<BR>\n" );
document.write( "14-6=2L<BR>\n" );
document.write( "8=2L<BR>\n" );
document.write( "L=8/2<BR>\n" );
document.write( "L=4 inches\r<BR>\n" );
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document.write( "Now we will find the diagonal of the rectangle\r<BR>\n" );
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document.write( "Diagonal= sqrt(4^2 + 3^2)<BR>\n" );
document.write( "D=sqrt(16 + 9)<BR>\n" );
document.write( "D=Sqrt(25)<BR>\n" );
document.write( "D=5 </SPAN>\n" );
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