document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44787>Question 44787</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this question:\r<BR>\n" );
document.write( "\n" );
document.write( "The expression Pi r^2 gives the area of a circle with radius r. How many square meters of wheat were destroyed when an alien ship made a crop circle of diameter 25 meters in the wheat field at the Southwest Ranch? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29678 by </B><A HREF=/tutors/aboutme.mpl?userid=Chris435435><B>Chris435435(8)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Chris435435><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> They gave you the diameter of the circle in the question.  The diameter of a circle is equivalent to twice its radius.  That is:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=d=2r ALIGN=MIDDLE  ALT=\"d=2r\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  We know from the question that the diameter of this crop circle is 25 meters.  So let's plug that in to the formula and that'll give us the radius of the circle.  \r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=25=2r ALIGN=MIDDLE  ALT=\"25=2r\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=25%2F2 ALIGN=MIDDLE  ALT=\"r=25%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r=12.5 ALIGN=MIDDLE  ALT=\"r=12.5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "Now that we know the radius, which is 12.5 meters.  Let's plug that into the formula for the area of the circle to get our answer:\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=pi%2A%2812.5%29%5E2 ALIGN=MIDDLE  ALT=\"A=pi%2A%2812.5%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=490.87 ALIGN=MIDDLE  ALT=\"A=490.87\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "You also could compute <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12.5%5E2 ALIGN=MIDDLE  ALT=\"12.5%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > and leave <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi ALIGN=MIDDLE  ALT=\"pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > alone.  In that case,\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=156.25pi ALIGN=MIDDLE  ALT=\"A=156.25pi\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );