document.write( "Question 44778This question is from textbook intermediate algebra
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document.write( ": here is another i am having problems with\r
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document.write( "2x^2 + 5x - 2 = 0 this is on completing the square to solve \n" );
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Algebra.Com's Answer #29676 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2x^2 + 5x - 2 = 0 this is on completing the square\r \n" ); document.write( "\n" ); document.write( "Divide thru by 2 to get:\r \n" ); document.write( "\n" ); document.write( "x^2+(5/2)x =0 \n" ); document.write( "Complete the square on the left side to get: \n" ); document.write( "x^2+(5/2)x+(5/4)^2 = 1 + (5/4)^2\r \n" ); document.write( "\n" ); document.write( "(x+(5/4))^2 = 21/16 \n" ); document.write( "Take the square root of both sides to get:\r \n" ); document.write( "\n" ); document.write( "x+(5/4) = (1/4)sqrt21 or (x+(5/4))=-(1/4)sqrt21 \n" ); document.write( "Then: \n" ); document.write( "x=-(5/4)+(1/4)sqrt21 or x=-(5/4 )-(1/4)(sqrt21\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |