document.write( "Question 44778This question is from textbook intermediate algebra
\n" ); document.write( ": here is another i am having problems with\r
\n" ); document.write( "\n" ); document.write( "2x^2 + 5x - 2 = 0 this is on completing the square to solve
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Algebra.Com's Answer #29676 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2x^2 + 5x - 2 = 0 this is on completing the square\r
\n" ); document.write( "\n" ); document.write( "Divide thru by 2 to get:\r
\n" ); document.write( "\n" ); document.write( "x^2+(5/2)x =0
\n" ); document.write( "Complete the square on the left side to get:
\n" ); document.write( "x^2+(5/2)x+(5/4)^2 = 1 + (5/4)^2\r
\n" ); document.write( "\n" ); document.write( "(x+(5/4))^2 = 21/16
\n" ); document.write( "Take the square root of both sides to get:\r
\n" ); document.write( "\n" ); document.write( "x+(5/4) = (1/4)sqrt21 or (x+(5/4))=-(1/4)sqrt21
\n" ); document.write( "Then:
\n" ); document.write( "x=-(5/4)+(1/4)sqrt21 or x=-(5/4 )-(1/4)(sqrt21\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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