document.write( "Question 71096: \"3 Pipes of different sizes are filling up a pool. Pipe1 fills it up a third of the time that it takes Pipe3, and Pipe2 fills it up a half of the time that it takes Pipe3. How long will it take each pipe to fill up the pool by itself?\"\r
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document.write( " -if you set up a table, i'm not sure where the variable would go, or when you set up the equation[[Pipe 1 work done + Pipe 2 work done + Pipe 3 work done = ?]] should that ? be a 1, for one hour, or a 3, for the 3 hours it took to fill up the pool with all of the pipes? \n" );
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Algebra.Com's Answer #296756 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! It doesn't necessarily take three hours for all three pipes to fill the pool. To solve this problem, let's take pipe 3 as our starting point. To fill the pool, pipe 3 working alone would take 1/x time. Since pipe 1 takes 1/3rd the time, it would be represented by 1/1x/3. Likewise, pipe 2 would be 1/1x/2. To fill one pool our equation would be: 1/x + 2/x + 3/x = 1 whole pool. X(1/x + 2/x + 3/x) = (1)X. 1 + 2 + 3 = X, or X = 6 hours for one whole pool. The other times are 1/2 * 6, or 3 hours, and 1/3 * 6, or 2 hours to fill a pool. Checking: 1/2 + 1/3 + 1/6 = 1. \n" ); document.write( " |