document.write( "Question 71096: \"3 Pipes of different sizes are filling up a pool. Pipe1 fills it up a third of the time that it takes Pipe3, and Pipe2 fills it up a half of the time that it takes Pipe3. How long will it take each pipe to fill up the pool by itself?\"\r
\n" ); document.write( "\n" ); document.write( " -if you set up a table, i'm not sure where the variable would go, or when you set up the equation[[Pipe 1 work done + Pipe 2 work done + Pipe 3 work done = ?]] should that ? be a 1, for one hour, or a 3, for the 3 hours it took to fill up the pool with all of the pipes?
\n" ); document.write( "

Algebra.Com's Answer #296756 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
It doesn't necessarily take three hours for all three pipes to fill the pool. To solve this problem, let's take pipe 3 as our starting point. To fill the pool, pipe 3 working alone would take 1/x time. Since pipe 1 takes 1/3rd the time, it would be represented by 1/1x/3. Likewise, pipe 2 would be 1/1x/2. To fill one pool our equation would be: 1/x + 2/x + 3/x = 1 whole pool. X(1/x + 2/x + 3/x) = (1)X. 1 + 2 + 3 = X, or X = 6 hours for one whole pool. The other times are 1/2 * 6, or 3 hours, and 1/3 * 6, or 2 hours to fill a pool. Checking: 1/2 + 1/3 + 1/6 = 1. \n" ); document.write( "
\n" );