document.write( "Question 44788: Please help. Not sure what book this comes from.\r
\n" ); document.write( "\n" ); document.write( "Solve. W=Fg/a(h1-h0) for h0. Not sure how to indicate that the 1 and 0 are lower than the h. I'm not sure what to do with the Fg/a, but I came up with h1=h0/h0-1.\r
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Algebra.Com's Answer #29675 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Solve. W=Fg/a(h1-ho) for ho\r
\n" ); document.write( "\n" ); document.write( "It is hard to tell if your (h1-ho) is in the numerator or
\n" ); document.write( "the denominator. I'll assume it is the numerator as follows:\r
\n" ); document.write( "\n" ); document.write( "W=(Fg/a)(h1-ho)
\n" ); document.write( "Multiply both sides by a to get:
\n" ); document.write( "Wa=F(h1-ho)
\n" ); document.write( "Divide both sides by F to get:
\n" ); document.write( "(Wa/F)=h1-ho
\n" ); document.write( "Subtract h1 from both sides to get:
\n" ); document.write( "(Wa/F)-h1=-ho
\n" ); document.write( "Multiply both sides by -1 to get:
\n" ); document.write( "ho=-(Wa/F)+h1\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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