document.write( "Question 426442: Solve log base 6 of x + log base 6 of (x+16)=2 \n" ); document.write( "

Algebra.Com's Answer #296687 by Gogonati(855) $\"\"$ $\"About$

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Solution;logx +log(x+16)=log36 because log base 6 of 36 is equal 2.
\n" ); document.write( " Now base on the logarithm properties we write:\r
\n" ); document.write( "\n" ); document.write( " log x(x+16)=log36 => x(x+16)=36 => $\"x%5E2%2B16x-36=0\"$ \r
\n" ); document.write( "\n" ); document.write( " The roots of this equation are: $\"x=%28-16%2B-+4sqrt%287%29%29%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+x=-8%2B-+2%2Asqrt%287%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Answer: The solution set is the empty set because the two roots are negative. \n" ); document.write( "

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