document.write( "Question 426354: In a container there are 12 ounces of a solution that is 80% acid. how many ounces of pure water must be added to produce a mixture that is 20% acid solution? \n" ); document.write( "
Algebra.Com's Answer #296670 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! In a container there are 12 ounces of a solution that is 80% acid. how many ounces of pure water must be added to produce a mixture that is 20% acid solution?\r \n" ); document.write( "\n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "let x=ounces of pure water to be added. \n" ); document.write( "note that the amount of acid does not change. We are just adding more water to get a weaker concentration of acid. \n" ); document.write( ".80(12)=.2(12+x) \n" ); document.write( "9.6=2.4+.2x \n" ); document.write( ".2x=9.6-2.4=7.2 \n" ); document.write( "x=7.2/.2=36 \n" ); document.write( "ans \n" ); document.write( "36 ounces of pure water must be added to produce a mixture that is 20% acid solution?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |