document.write( "Question 426472: Two planes took off from an airport at the same time and flew in opposite directions. One plane traveled 120 miles per hour faster than the other. At the end of three hours the planes were 1500 miles apart What was the average speed of the slower plane? \n" ); document.write( "
Algebra.Com's Answer #296661 by mananth(16946)\"\" \"About 
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Plane A x mph
\n" ); document.write( "Plane B x+120 mph
\n" ); document.write( "..
\n" ); document.write( "They are going away from each other.
\n" ); document.write( "So add up their speed.
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\n" ); document.write( "combined speed = x+x+120
\n" ); document.write( "=2x+120
\n" ); document.write( "Time = 3 hours
\n" ); document.write( "Distance = 1500 miles
\n" ); document.write( "Distance = speed * time
\n" ); document.write( "(2x+120 )*3=1500
\n" ); document.write( "6x+360= 1500
\n" ); document.write( "6x=1500 -360
\n" ); document.write( "6x=1140
\n" ); document.write( "/6
\n" ); document.write( "x=190 mph Plane A
\n" ); document.write( "Plane B 190+120 =310mph
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