document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=426377>Question 426377</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Having trouble with order of operations and understanding how to get to the answer which is -3.  Thanks.\r<BR>\n" );
document.write( "\n" );
document.write( "(2a-3)/6 = 2a/3+1/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #296647 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=296647\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2a-3)/6 = 2a/3 + 1/2<BR>\n" );
document.write( "2a-3=4a+3 multiply each side by 6.<BR>\n" );
document.write( "-2a=6<BR>\n" );
document.write( "a=-3<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );